9x^4-41x^2-20=0

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Solution for 9x^4-41x^2-20=0 equation:


Simplifying
9x4 + -41x2 + -20 = 0

Reorder the terms:
-20 + -41x2 + 9x4 = 0

Solving
-20 + -41x2 + 9x4 = 0

Solving for variable 'x'.

Factor a trinomial.
(-4 + -9x2)(5 + -1x2) = 0

Subproblem 1

Set the factor '(-4 + -9x2)' equal to zero and attempt to solve: Simplifying -4 + -9x2 = 0 Solving -4 + -9x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -9x2 = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -9x2 = 0 + 4 -9x2 = 0 + 4 Combine like terms: 0 + 4 = 4 -9x2 = 4 Divide each side by '-9'. x2 = -0.4444444444 Simplifying x2 = -0.4444444444 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(5 + -1x2)' equal to zero and attempt to solve: Simplifying 5 + -1x2 = 0 Solving 5 + -1x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1x2 = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1x2 = 0 + -5 -1x2 = 0 + -5 Combine like terms: 0 + -5 = -5 -1x2 = -5 Divide each side by '-1'. x2 = 5 Simplifying x2 = 5 Take the square root of each side: x = {-2.236067978, 2.236067978}

Solution

x = {-2.236067978, 2.236067978}

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